k^2+4k-12=(k+6)(k-)

Solution for k^2+4k-12=(k+6)(k-) equation:

k^2+4k-12=(k+6)(k-)

We move all terms to the left:

k^2+4k-12-((k+6)(k-))=0

We add all the numbers together, and all the variables

k^2+4k-((k+6)(+k))-12=0

We multiply parentheses ..

k^2-((+k^2+6k))+4k-12=0


We calculate terms in parentheses: -((+k^2+6k)), so:

(+k^2+6k)

We get rid of parentheses

k^2+6k

Back to the equation:

-(k^2+6k)


We add all the numbers together, and all the variables

k^2+4k-(k^2+6k)-12=0

We get rid of parentheses

k^2-k^2+4k-6k-12=0

We add all the numbers together, and all the variables

-2k-12=0

We move all terms containing k to the left, all other terms to the right

-2k=12

k=12/-2

k=-6